Vapor pressure of liquid Diethyl ether (data page)
log10 of diethyl ether vapor pressure. uses formula:
log
e
p
m
m
h
g
=
{\displaystyle \scriptstyle \log _{e}p_{mmhg}=}
log
e
(
760
101.325
)
−
12.4379
log
e
(
t
+
273.15
)
−
6340.514
t
+
273.15
+
95.14704
+
1.412918
×
10
−
05
(
t
+
273.15
)
2
{\displaystyle \scriptstyle \log _{e}({\frac {760}{101.325}})-12.4379\log _{e}(t+273.15)-{\frac {6340.514}{t+273.15}}+95.14704+1.412918\times 10^{-05}(t+273.15)^{2}}
obtained cheric
Comments
Post a Comment